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6 January, 20:49

Find the area of a parallelogram with sides 6 and 12 and an angle of 60

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  1. 6 January, 21:05
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    Hello,

    Let's assume h the heigth of the parallelogram

    h/6=sin 60°==>h=√3/2*6=3√3

    Area=3√3 * 12=36√3
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