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11 May, 02:36

Find the zeros of f (x) = (x - 3) ^2 - 49

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  1. 11 May, 02:59
    0
    We have the function f (x) = (x-3) ^2-49.

    This equals ...

    0 = (x-3) ^2 - 49

    Add 49.

    49 = (x-3) ^2

    Square both sides.

    ±7 = x-3

    ± 10 = x
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