Find the term that must be added to the equation x2-6x=7 to make it into a perfect square.

x²-6x = 7

First we have get rid of that 7 from the right side and move it to the left side. To move 7 to the left side, we have to subtract 7 from both sides.

x²-6x-7 = 7-7

x²-6x-7 = 0

To make this equation a perfect square, first we have to check the x term. Here - 6x given. We have to divide the co-efficient of x by 2, and then we have to add the square of it.

The co-efficient of x is - 6 here. Dividing it by 2, we will get - 6/2 = - 3.

We will have to add (-3) ² here. (-3) ² is 9. So in the place of - 7, we have to make 9, to make the equation a perfect square.

9 - (-7) = 9+7 = 16

So by adding 16 to the left side, we can make the equation a perfect square.

x²-6x-7+16 = 0

x²-6x+9 = 0

x²-6x + (-3) ² = 0

(x-3) ² = 0