How to solve 4 (7-3x) = 7 (4-2x)

Question

Bailee Salazar

Mathematics

22 July, 10:40

How to solve 4 (7-3x) = 7 (4-2x)

+4

Answers (2)

Know the Answer?

Aidyn Potts · Answer 1

x=0

Step-by-step explanation:

4 (7-3x) = 7 (4-2x)

Distribute

28 - 12x = 28 - 14x

Subtract 28 from each side

-12x = - 14x

Add 14x to each side

-12x+14x = - 14x+14x

2x=0

x = 0

Alden Randall · Answer 2

Step-by-step explanation:

First, you distribute the 4 and 7 to the stuff inside the parentheses 28 - 12x = 28 - 14x then add 28 to both sides - 12x = - 14x then add 14x to both sides 2x = 0 then divide both sides by 2 x = 0