29 January, 15:39
How to solve 4 (7-3x) = 7 (4-2x)
29 January, 16:57
First, you distribute the 4 and 7 to the stuff inside the parentheses 28 - 12x = 28 - 14x then add 28 to both sides - 12x = - 14x then add 14x to both sides 2x = 0 then divide both sides by 2 x = 0
29 January, 17:16
4 (7-3x) = 7 (4-2x)
28 - 12x = 28 - 14x
Subtract 28 from each side
-12x = - 14x
Add 14x to each side
-12x+14x = - 14x+14x
x = 0
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