There are 9 children playing in a playground. In a game, they all have to stand in a line such that the youngest child is at the beginning of the line. How many ways can the children be arranged in the line?

a. 40,320

b. 362,880

c. 16,777,216

d. 387,420,489

Question

Kamari Hull

Mathematics

17 December, 04:46

There are 9 children playing in a playground. In a game, they all have to stand in a line such that the youngest child is at the beginning of the line. How many ways can the children be arranged in the line?

a. 40,320

b. 362,880

c. 16,777,216

d. 387,420,489

+5

Answers (1)

Know the Answer?

Stich · Answer 1

In order to calculate how many ways the children can be arranged in the line, all you have to do is multiply the number of children. Here's how to do it since there are 9 children:

9*8*7*6*5*4*3*2*1 = 362,880

The correct answer is B.

There are 9 children playing in a playground. In a game, they all have to stand in a line such that the youngest child is at the beginning of the line. How many ways can the children be arranged in the line?a. 40,320b. 362,880c. 16,777,216d. 387,420,489

There are 9 children playing in a playground. In a game, they all have to stand in a line such that the youngest child is at the beginning of the line. How many ways can the children be arranged in the line?

a. 40,320

b. 362,880

c. 16,777,216

d. 387,420,489