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6 October, 04:51

Find four consecutive odd integers such that the sum of the first three exceeds the fourth by 18?

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  1. 6 October, 05:14
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    Let, numbers = x, (x+2), (x+4), (x+6)

    A. T. Q,

    x+x+2+x+4 = x+6+18

    3x+6 = x+24

    3x-x = 24-6

    2x = 18

    x = 9

    Numbers would be 9, 11, 13, 15
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