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22 June, 11:40

Find the sum of all integers between 84 and 719 which are exactly divisible by 5

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  1. 22 June, 11:46
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    50,800

    Step-by-step explanation:

    The first integer between 84 and 719 that's divisible by 5 is 85.

    The last integer between 84 and 719 that's divisible by 5 is 715.

    The sum of an arithmetic sequence is:

    S = n (a₁ + a) / 2

    where n is the number of terms, a₁ is the first term, and a is the last term.

    To find the number of terms:

    n = (a - a₁) / d + 1

    where d is the common difference.

    Here, a = 715, a₁ = 85, and d = 5.

    n = (715 - 85) / 5 + 1

    n = 127

    S = 127 (85 + 715) / 2

    S = 50,800
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