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15 December, 18:51

Alan solved the proportion StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction as shown. StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction. (8) (x) = (25) (200). 8 x = 5,000. StartFraction 8 x over 8 EndFraction = StartFraction 5,000 over 8 EndFraction. X = 625. What is Alan's error? He got the wrong product when he multiplied 25 by 200. He got the wrong quotient when he divided 5,000 by 8. He mixed up the positions of 8 and 25 in the equation (8) (x) = (25) (200). He mixed up the positions of 8 and 200 in the equation (8) (x) = (25) (200)

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Answers (2)
  1. 15 December, 18:55
    0
    C on edge

    Step-by-step explanation:

    Alan solved the proportion StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction as shown.

    StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction. (8) (x) = (25) (200). 8 x = 5,000. StartFraction 8 x over 8 EndFraction = StartFraction 5,000 over 8 EndFraction. X = 625.
  2. 15 December, 19:05
    0
    Step-by-step explanation:

    The proportion that Alan solved was

    x/200 = 8/25

    His working as shown was

    (8) (x) = (25) (200)

    8x = 5000

    He divided both sides of the equation by 8. It became

    8x/8 = 5000/8

    x = 625

    The correct steps are

    25x = 200 * 8 = 1600

    Dividing both sides of the equation by 25, it becomes

    x = 1600/25

    x = 64

    Alan's error were:

    1) He got the wrong product when he multiplied 25 by 200.

    2) He got the wrong quotient when he divided 5,000 by 8.
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Home » Mathematics » Alan solved the proportion StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction as shown. StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction. (8) (x) = (25) (200). 8 x = 5,000.
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