A bean plant grows at a constant rate for a month. After 10 days, the plant is

35 centimeters tall. After 20 days, the plant is 55 centimeters tall.

Which equation models the height of the plant, y, after x days?

A. y+35 = 2 (x+10)

B. y - 35 = 2 (x - 10)

C. y - 10 = 2 (x - 35)

D. y - 35 = 1/2 (x - 10)

Question

Ronald Lamb

Mathematics

24 June, 08:08

A bean plant grows at a constant rate for a month. After 10 days, the plant is

35 centimeters tall. After 20 days, the plant is 55 centimeters tall.

Which equation models the height of the plant, y, after x days?

A. y+35 = 2 (x+10)

B. y - 35 = 2 (x - 10)

C. y - 10 = 2 (x - 35)

D. y - 35 = 1/2 (x - 10)

+5

Answers (1)

Know the Answer?

Ramon Robbins · Answer 1

B. y - 35 = 2 (x - 10)

Step-by-step explanation:

The height of the plant, y, after x days could be modeled by the equation

y-y0=k (x-xo) (1), where y0 was the initial height at 'x0'th. day, and k is the constant of proportionality. From equation (1), k could be evaluated as follows:k = (y-y0) / (x-x0) From the problem statement, we may determine k by plugging in the given values, e. g. y0 = 35, x0=10, y=55, x=20. Thus, k = (55-35) / (20-10) = 2Therefore, the model equation becomesy-35=2 (x-10)

A bean plant grows at a constant rate for a month. After 10 days, the plant is35 centimeters tall. After 20 days, the plant is 55 centimeters tall.Which equation models the height of the plant, y, after x days?A. y+35 = 2 (x+10)B. y - 35 = 2 (x - 10)C. y - 10 = 2 (x - 35)D. y - 35 = 1/2 (x - 10)