A jar contains three red marbles and five green marbles. A marble is drawn at random and not replaced. A second marble is then drawn from the jar. Find the probability that the first marble is red and the second marble is green.

Question

Karly Villanueva

Mathematics

15 June, 05:21

A jar contains three red marbles and five green marbles. A marble is drawn at random and not replaced. A second marble is then drawn from the jar. Find the probability that the first marble is red and the second marble is green.

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Answers (2)

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Bryson Mejia · Answer 1

P (red then green) = 5/8 * 3/7 = 15/56

Step-by-step explanation: Since this is a logical "and" case, we have to multiply the separate events' probabilities ... thus P (red then green) = 5/8 * 3/7 = 15/56

Marissa Roman · Answer 2

3/28

Step-by-step explanation:

3 red + 5 green = 8 marbles in the jar

1st marble:

P (red) = number of red / total = 3/8

We keep the marble

2 red + 5 green = 7 marbles in the jar

P (green) = number of green / total = 2/7

P (red, keep, green) = P (red) * P (green) = 3/8*2/7 = 6/56 = 3/28