Which formula can be used to find the nth term in a geometric sequence where a1=3 and r=2?

A (n) = a (1) * r^ (n-1)

a (n) = 3*2^ (n-1)

Hope I don't mess up for your sake.

1st term = a₁ = 3, r=2

1st a₁ = 3 x 2⁰

2nd a₂ = 3 x 2¹

3rd a₃ = 3 x 2²

4th a₄ = 3 x 2³

5th a₅ = 3 x 2⁴

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nth : a (n) = 3 x 2 ⁽ⁿ-¹)

Note when that the subscript of a is the same as the exponent mines 1