A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. The second product's unit volume is 3 cu ft, and it weighs 40 lbs. If the company's trucks have 2300 cu ft of space and can carry 21,000 lbs., how many units of each can be transported in a single shipment with one truck?

116 units of the first product

380 units of the second product

Step-by-step explanation:

Product 1 has a unit volume of 10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300 ... (1)

50X+40Y=21000 ... (2)

Solving the system of equations:

10X+3Y=2300 ... (1)

10X=2300-3Y

X = (2300-3Y) / 10

Substituting X in (2) we have:

50X+40Y=21000

50[ (2300-3Y) / 10]+40Y=21000

50[ (2300/10) - (3Y/10) ]+40Y=21000

50[230 - (3Y/10) + 40Y=21000

11500 - (150Y/10) + 40Y=21000

11500-15Y+40Y=21000

11500+25Y=21000

25Y=21000-11500

25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300 ... (1)

10X+3 (380) = 2300

10X+1140=2300

10X=2300-1140

10X=1160

X=116

So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.