Ask Question
28 April, 17:14

A ball is thrown from a height of 160 feet with an initial downward velocity of 12 ft/s.

. The ball's height h (in feet) after t seconds is given by the following.

h = 160 - 12t - 16t^2

How long after the ball is thrown does it hit the ground?

Round your answer (s) to the nearest hundredth.

+4
Answers (1)
  1. 28 April, 17:39
    0
    Step-by-step explanation:

    Solve the quadratic equations for h = 0

    Quadratic formula:

    (12 + - sqrt (144-4 (-16) (160))) / 32

    (12 + - sqrt (10384)) / 32

    t = - 2.81 (disregard this because a negative doesn't make since in this context)

    t=3.56
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A ball is thrown from a height of 160 feet with an initial downward velocity of 12 ft/s. . The ball's height h (in feet) after t seconds is ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers