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24 October, 23:03

Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg

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  1. 24 October, 23:06
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    1813.137 KJ

    Step-by-step explanation:

    potential energy of the body = mgH

    where m is mass in Kg, g = 9.81 m/sec^2 and H = height in m

    here m = 1000 kg, g = 9.81 m/s^2 and H = 607 feet = 607*0.305 = 185.135 m

    hence the potential energy p = 1000*9.81*185.135 = 1813137.2 J

    = 1813.137 KJ

    hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ
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