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Roxanne
Mathematics
22 June, 20:55
Simplify 2 (f^4) ^2 f^3 divided by 6f^9
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Lea Kirk
22 June, 21:12
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((2f^4) ^2*f^3) / (6f^9)
pertinent rules of exponents:
(a^b) ^c=a^ (b*c), (a^b) (a^c) = a^ (b+c), and (a^b) / (a^c) = a^ (b-c) so
(2f^ (4*2) * f^3) / (6f^9)
(2f^8*f^3) / (6f^9)
(2f^ (8+3)) / (6f^9)
(2f^11) / (6f^9)
(2/6) (f^11/f^9)
(1/3) (f^ (11-9)
(1/3) (f^2)
(f^2) / 3
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