At a local plant sale, Janice was selling Golden Barrel Cactus plants and baby Saguaros. During the sale, she sold 5 times as many Saguaros ($6 each) as Golden Barrels ($10 each). She made a total of $720 during the plant sale. How many Saguaros did Janice sell?. A ... 18. B ... 40. C ... 72. D ... 90.

Question

Saniyah Potts

Mathematics

19 January, 16:07

At a local plant sale, Janice was selling Golden Barrel Cactus plants and baby Saguaros. During the sale, she sold 5 times as many Saguaros ($6 each) as Golden Barrels ($10 each). She made a total of $720 during the plant sale. How many Saguaros did Janice sell?. A ... 18. B ... 40. C ... 72. D ... 90.

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Answers (2)

Know the Answer?

Amare Daniels · Answer 1

The answer is D. 90 Saguaros.

Solution:

Let x = number of Golden Barrel Cactus plants; y = number of baby Saguaros

sold 5 times as many Saguaros as Golden Barrels: y = 5x

total of 720 dollars during plant sale: 6y + 10y = 720

Solving for x and y as two linear equations with two unknowns or by substitution method we get:

x = 18

y = 90

Courtney Carroll · Answer 2

Let x be the number of Golden Barrel Cactus Janice sold. By the representation, the number of Saguaros she sold was 5x. The total earnings she had from her goods were 6 (5x) for Saguaros and 10x for Golden Barrel. With her total earning reaching up to $720, the equation becomes

30x + 10x + 720; x = 18

18 is the number of Golden Barrel she sold and five times this number is the number of Saguaros. Thus, she sold 90 pieces of Saguaros.