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15 December, 20:04

The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.

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  1. 15 December, 20:12
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    D=2+20+2w=22+2w

    so the eqations would be l=20+2w and d=22+2w

    so when solving for the width, (20+2w) ^2+w^2 = (22+2w) ^2

    your equation would be : 400+80w+4w^2+w^2=484+44w+w^2

    the anwer would be 1.9226
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