Evaluate the integral (e^x) / ((e^2x) + 3) from 0 to infinity

So, from our equation

u = e^x

du/dx = e^x du = e^xdxthe integral would be:

du / (u^2 + 3)

Using the boundaries 1 to infinity

As, e^0 = 1. the solution for this integral will be

(1 / (3^0.5)) * arctan (u / (3^0.5)) Plugging the boundaries

(1 / (3^0.5)) * (90 - 30) = 60 / (3^0.5)

=0.6046