How do you represent the decimal 50 integer in binary?

50 = 5 * 10 + 0 * 1 (5 in the tens place, and 0 in units).

We can write each place as a power of ten:

50 = 5 * 10^1 + 0 * 10^0

Similarly for hexadecimal and binary, but then using powers of 16 and 2 respectively.

We need to find the digits of the hexadecimal form. Or in other words, we need to find a and b:

50 = a * 16 + b * 1

Simply divide 50 by 16 will get you a with some remainder, which is a multiple in units, and thus b:

50 / 16 = 3 (=a), remainder 2.

[2 / 1 = 2 (=b), remainder 0]

Thus 50 in hexadecimal is "32".

For binary, we need to do the division a couple of times more to find all digits.

50 = a * 32 + b * 16 + c * 8 + d * 4 + e * 2 + f * 1

50 / 32 = 1 (=a), remainder 18

18 / 16 = 1 (=b), remainder 2

2 / 8 = 0 (=c), remainder 2

2 / 4 = 0 (=d), remainder 2

2 / 2 = 1 (=e), remainder 0

[0 / 1 = 0 (=f), remainder 0]

We find that 50 in binary is "110010".