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19 October, 14:53

Y = x^2 - 2x; domain {-3, 0, 5}

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  1. 19 October, 15:05
    0
    range:{0,15}

    Step-by-step explanation:

    y=x²-2x

    domain:{-3,0,5}

    for range

    when x=-3

    y = (-3) ²-2 * (-3) = 9+6=15

    when x=0

    y=0-0=0

    when x=5

    y=5²-2*5=25-10=15

    range:{0,15}

    or

    y=x²-2x+1-1 = (x-1) ²-1

    when x=-3

    y = (-3-1) ²-1=16-1=15

    when x=0

    y = (0-1) ²-1=1-1=0

    when x=5

    y = (5-1) ²-1=16-1=15
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