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3 December, 03:35

Write a polynomial function with the zeros 1, - 2i

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  1. 3 December, 03:48
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    F (x) = (x - 1) (x + 2i) (x - 2i), because the zeroes are 1, - 2i, + 2i;

    f (x) = (x - 1) (x^2 - 4i^2) = (x - 1) (x^2 + 4) = x^3 - x^2 + 4x - 4;
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