The area of a rectangle is 40 square feet. What could be the perimeter of the rectangle? how is this problem solved.

The side lengths to get an area of 40 could be 8 and 5

Area = length x width

So if one side is 8 and the other is 5 then it will have to be the same on the opposite side of the rectangle

Perimeter = side + side + side + side

So it is 8+8+5+5 = 16+10 = 26 feet

This is just one answer, there is more than one correct answer for this problem

A possible perimeter for the rectangle would be 28

Area=L x W

40/10=4

Width=4, Length=10

Perimeter=L+L+W+W

4+4+10+10=28