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23 December, 07:24

Set F1 = 5N at 0 degrees, F2 = 5N at 90 degrees, F3 = 5N at 270 degrees and run the simulation. Using trigonometry, what net force of F4 in the negative x-direction is necessary to produce an angle of 15 degrees between F2 and F3 and the y-axis? Set F4 to that value and run the simulation. Does the angle formed approximate 15 degrees?

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  1. 23 December, 07:50
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    Answer: find the solution in the explanation

    Step-by-step explanation:

    Let's use resolution of forces by resolving into x - component and y - component.

    X - component.

    Sum of forces = F1 - F3 - F4cos 15

    Sum of forces = 0

    5 - 5 - 0.97F4 = 0

    - 0.97 F4 = 0

    F4 = 0

    Y - component

    Sum of forces = F2 + F4 sin 15

    Sum of forces = 0

    5 + 0.26F4 = 0

    0.26 F4 = - 5

    F4 = - 5/0.26

    F4 = - 19.23 N

    Simulating F4 back into the equation

    Sum of forces = F1 - F3 - F4cos 15

    - F4cos Ø = 0

    - (-19.23) cos Ø = 0

    Cos Ø = 0

    Ø = 1

    Does the angle formed approximate 15 degrees? NO
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