Y = (x^2-6x+14) Labeling the vertex

I leaerned this neat trick

you don't need to convert to vertex form

where

y=ax^2+bx+c

the x value of the vertex is - b/2a

the y value is found by inserting the x value of the vertex into the equation

so

1x^2-6x+14

-b/2a = - (-6) / 2 (1) = 6/2=3

plug that in

y=x^2-6x+14

y=3^2-6 (3) + 14

y=9-18+14

y=5

the vertex is (3,5)