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24 August, 00:26

Jude says that the volume of a square pyramid with base edges of 12 in and a height of 10 in is equal to the volume of a cylinder with a radius of 6.77 in and a height of 10 in. Jude rounded his answers to the nearest whole numbers. Examine Jude's calculations. Is he correct?

Volume of Square Pyramid Volume of Cylinder

V = one third B (h) V = one thirdπr2h

V = one third (144) (10) V = one thirdπ (6.772) (10)

V = one third (1440) one thirdπ (45.8329) (10)

V = 480 in3 V = one thirdπ (458.329)

V ≈ 480 in3

Yes, his calculations are correct and the volumes for figures are equal.

No, he made a mistake in solving for the volume of the cylinder.

Yes, but he made a mistake in solving for the volume of the square pyramid.

No, he made a mistake in solving for the volume of both figures.

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Answers (1)
  1. 24 August, 00:40
    0
    No, not correct

    Step-by-step explanation:

    Square pyramid volume: (1/3) (base area) (height). In this case,

    V = (1/3) * (12 in) ^2 * (10 in) = 480 in^3 = 480 in^3

    Cylinder volume: (base area) * (height). In this case,

    V = (3.14) * (6.77 in) ^2 * (10 in) = 452.12 in^3.

    No, Jude is not correct; the 480 in^3 volume of the square pyramid is not the same as the 452.12 in^3 volume of the cylinder.
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