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2 November, 19:28

What is the fourth term of the expansion of the binomial (2x + 5) ^5?

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  1. 2 November, 19:45
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    From pascal's pyramid

    4th term of 5th order is 10

    (coefficient - let's call c)

    for (a + b) ^n the m-th term is

    c[a^ (n-m+1) ][b^ (m-1) ]

    sample (a + b) ^3

    1st term : c1 (a^3b^0) = c1a^3

    2nd term : c2 (a^2b^1)

    3rd term : c3 (a^1b^2)

    4th term : c4 (a^0b^3) = c4b^3

    ... notice order of 2 variables

    one decreases from max to 0, the other increases from 0 to max AND

    sum of orders in each term must equal to the order of the binomial

    for (2x + 5) ^5, 4th term is

    10[ (2x) ^ (5-4+1) ][5^ (4-1) ]

    = 10[ (2x) ^2][5^3) ]

    = ...
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