Ask Question
14 February, 01:38

The area of a rectangle is 52in^2 the length of the rectangle is 9 in longer than the width what is the width

+5
Answers (1)
  1. 14 February, 01:49
    0
    Area (A) = 52in^2

    Width (W) = ?

    Length (L) = W+9

    Area = LxW

    52 = (W+9) (W)

    52=W^2 + 9W

    0 = W^2 + 9W-52

    0 = (W+13) (W-4)

    W+13=0 then W=-13 and W-4=0 then W=4

    We will only use the positive solution of 4 since distance is positive.

    W=4
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The area of a rectangle is 52in^2 the length of the rectangle is 9 in longer than the width what is the width ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers