Ask Question
21 December, 12:08

Factor. 25m^100-121n^16

(5 m10 - 11 n4) (5 m10 + 11 n4) (5 m50 - 11 n8) 2 (5 m50 - 11 n8) (5 m50 + 11 n8) (5 m10 - 11 n4) 2

+4
Answers (1)
  1. 21 December, 12:38
    0
    25m¹⁰⁰-121n¹⁶

    this question is a difference of squares. the basic equations is when you get 2 square numbers and you have to find their difference;

    x²-y² = (x + y) (x-y)

    you have to then find the product of these factors.

    the question given can be rewritten to write the numbers in their square forms

    25m¹⁰⁰ - 5²m⁵⁰ˣ² - square root - 5m⁵⁰

    121n¹⁶ - 11²n⁸ˣ² - square root - 11n⁸

    we have to then factorise them

    the answer for 25m¹⁰⁰-121n¹⁶ = (5m⁵⁰ - 11n⁸) (5m⁵⁰ + 11n⁸)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Factor. 25m^100-121n^16 (5 m10 - 11 n4) (5 m10 + 11 n4) (5 m50 - 11 n8) 2 (5 m50 - 11 n8) (5 m50 + 11 n8) (5 m10 - 11 n4) 2 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers