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21 November, 20:00

Identify the following conic section: 11x^2-3y^2 - 88x+18y=116=0

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  1. 21 November, 20:06
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    11x^2-3y^2 - 88x+18y=116

    11x^2 - 88x - 3y^2 + 18y = 116

    11 (x^2-8x) - 3 (y^2+9y) = 116

    because of the subtraction of the y^2 we know it is a hyperbola
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