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26 December, 03:49

How many solutions does this quadratic equation have?

6p^2-7p+5=0

+1
Answers (2)
  1. 26 December, 04:00
    0
    No Real soultions

    Step-by-step explanation:

    solve by using the discriminant

    b^2-4ac

    (-7) ^2 - 4 x 6 x 5

    = - 71

    negative--->-71<0 no real solution
  2. 26 December, 04:11
    0
    It has no real solution.

    Step-by-step explanation:

    6p^2 - 7p + 5 = 0

    For this equation: a = 6, b = - 7, c = 5

    6p^2 + - 7p + 5 = 0

    Step 1: Use quadratic formula with a=6, b=-7, c=5.

    p = - b ± √b^2 - 4ac/2a

    p = - (-7) ± √ (-7) ^2 - 4 (6) (5) / 2 (6)

    p = 7 ± √-71/12
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