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Yosef Hayes
Mathematics
8 February, 21:46
For whаt vаluе оf x does 3^4 х = 27^x-3?
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Solomon Crosby
8 February, 22:09
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x = - 9
Step-by-step explanation:
3^4 х = 27^ (x-3)
Replace 27 with 3^3
3^4 х = 3^3^ (x-3)
We know that a^b^c = a^ (b*c)
3^4 х = 3^ (3 (x-3))
Since the bases are the same, the exponents are the same
4x = 3 (x-3)
Distribute
4x = 3x-9
Subtract 3x from each side
4x-3x = 3x-3x-9
x = - 9
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