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Lance Campbell
Mathematics
13 April, 18:27
What are the zeros of the equation 4x^2 = 4?
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Guadalupe Donovan
13 April, 18:40
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4x^2 = 4
4x^2 - 4 = 0
4 (x^2 - 1) = 0
x^2 - 1 = 0/4
x^2 - 1 = 0
(x-1) (x+1) = 0 << - - - use the difference of squares rule
x-1 = 0 or x+1 = 0
x = 1 or x = - 1
The roots are x = 1 or x = - 1
Note: "Root" is another term for "solution" or "zero" of a function
If we replace x with 1 or - 1 back in the original equation, it leads to a true equation.
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