Solve n3 + 2n2 - 15n = 0 by factoring.

N³ - 2n² - 15n = 0

"n"

n (n² + 2n - 15) = 0

n = 0

n² + 2n - 15 = 0

Δ = (2) ² - 4 (1) (-15)

Δ = 4 + 60 = 64

n' = (-2+8) / 2 = 6/2 = 3

n'' = (-2-8) / 2 = - 10/2 = - 5

Solution:

S {-5, 0, 3 }

N^3+2n^2-15n=0

n (n^2+2n-15) = 0

n (n^2+5n-3n-15) = 0

n (n (n+5) - 3 (n+5)) = 0

n (n-3) (n+5) = 0

n={-5, 0, 3}