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21 January, 00:23

What is the solution to set to the inequality (4x-3) (2x-1) _>0 a) x b) x 4/3 c) x d) x

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  1. 21 January, 00:31
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    (4x - 3) (2x - 1) ≥ 0

    4x - 3 ≥ 0 or 2x - 1 ≤ 0

    + 3 + 3 + 1 + 1

    4x ≥ 3 2x ≤ 1

    4 4 2 2

    x ≥ ³/₄ x ≤ ¹/₂

    x ∈ [-∞, ¹/₂] ∧ [³/₄, ∞]

    The answer is C.
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