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2 June, 05:29

What is the sum of the measure of the interior angles of a regular polygon if each exterior angle measures 72 degrees

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  1. 2 June, 05:39
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    Sum of interior and exterior angle is 180 so

    Interior angle = 180-72=108

    Now we need to find the no of sides of the polygon = n We know that interior angle of n-sides is given by

    (n-2) * 180n

    We have

    (n-2) * 180=108n

    or

    180n-360=108n

    or

    72n=360

    n=5 sides so there are 5 angles each of 108 degrees Sum of the interior angles=108+108+108+108+108=540 ...

    To find the measure of each exterior angle of a regular polygon, you just divide 360 degrees by the number of sides.
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