a plane has 32 seats in class A and 50 seats in class B whose sale represents a total of € 14,600. However, only 10 seats have been sold in class A and 40 seats in class B. A total of € 7,000 was obtained What is the price of a seat in each class?

The two equations would be

32a+50b=14600

10a+40b=7000

To solve, we need to eliminate one variable ... let's eliminate b

4 (32a+50b=14600) - > 128a+200b=58400

-5 (10a+40b=7000) - > - 50a-200b=-35000

So when we add them together' we get 78a = 23400

So solve that and a = 300, so class a tickets cost 300 euros each

Substitute a=300 into first equation in the system of equations at the beginning and 32 (300) + 50b=14600 - > 9600+50b=14600 - > 50b = 5000 or b = 100, so the cost for class b tickets is 100 euros each