If cos 67 degrees is close to 2/5 which is closest to the length of no

PO=100cm

P=23 degrees

40 cm

Step-by-step explanation:

In the right triangle PNO:

∠N = 90° PO = 100cm (the hypotenuse of the triangle) ∠P = 23° ∠O = 90° - 23° = 67° side NO is adjacent to ∠O

By definition:

cos (β) = adjacent/hypotenuse

Replacing with data and solving for NO:

cos (∠O) = NO/PO

2/5 = NO/100

NO = (2/5) * 100

NO = 40