1. A 2012 survey conducted by the local paper in Columbus, Ohio one week before Election Day

asked voters whom they would vote for in the election of City Attorney. 37% said they would

vote for the Democratic candidate. On Election Day, 41% actually voted for the Democratic

candidate. The number 37% is what?

Question

Amare Singleton

Mathematics

3 November, 12:59

1. A 2012 survey conducted by the local paper in Columbus, Ohio one week before Election Day

asked voters whom they would vote for in the election of City Attorney. 37% said they would

vote for the Democratic candidate. On Election Day, 41% actually voted for the Democratic

candidate. The number 37% is what?

+1

Answers (1)

Know the Answer?

Marianna · Answer 1

The description again for the problem is listed throughout the section below on explanations.

Step-by-step explanation:

A 2012 survey conducted a week since Voting day because the local paper in Columbus asked voters whatever individual they might vote for the state attorney. 37% of respondents said that they'd vote for both the dem candidate. In reality, 41 percent voted for both the Democratic nominee on Elections Day.

The 37% is supported by a survey as well as being a factual estimate. The sample proportion is denoted by "P". Therefore,

⇒ P = 0.37

The specific proportion becomes supplied as a factor of 41% = 0.41. Since the importance of proportion is real. The proportion of community is represented as p or π

Hence p = 0.41.