How to solve 3|2d - 6| + 2 = 2

d = 3

Step-by-step explanation:

Firstly eliminate the modulus sign by multiplying the value inside with (-1)

; |2d - 6| = - 2d + 6 ... then substitute it back into the equation,

; 3 (-2d + 6) + 2 = 2

; - 6d + 18 + 2 = 2

; - 6d = - 18 - 2 + 2

; - 6d = - 18

; Hence the value of ...; d = 3