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Brennen Gill
Mathematics
22 February, 05:00
8/5+3y=6y-1/5 the solution is y=
+4
Answers (
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Shaun Woodward
22 February, 05:12
0
y = - 5 / 2 or y=1
Step-by-step explanation:
Step 1: Cross-multiply.
8 / 5+3y = 6y-1 / 5
(8) * (5) = (6y-1) * (5+3y)
40=18y^2+27y-5
Step 2: Subtract 18y^2+27y-5 from both sides.
40 - (18y^2+27y-5) = 18y^2+27y-5 - (18y^2+27y-5)
-18y2-27y+45=0
Step 3: Factor left side of equation.
-9 (2y+5) (y-1) = 0
Step 4: Set factors equal to 0.
2y+5=0 or y-1=0
y = - 5 / 2 or y=1
Answer:
y = - 5 / 2 or y=1
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