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18 June, 08:08

In standardized scores of achievement motivation that are normally distributed, the US group has a mean score of 35 with a standard deviation of 14. Higher scores correspond to more achievement motivation. Shamu scored in the top 20% of the test takers. What was her score?

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  1. 18 June, 08:13
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    x = 46.033

    Step-by-step explanation:

    mean score (μ) = 35

    standard deviation = 14

    shamu scored 20% i. e (0.2) of the test

    so

    we will take value from the z-table at 0.80 from the left of it.

    so z-value comes out to be =.78814

    using standard formula

    x = μ + z * σ

    x = 35 + 0.78814 * 14

    x = 46.033
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