If r and s are positive integers, each greater than 1, and if 11 (s-1) = 13 (r-1), what is the least possible value of (r+s) ?

The least value of (r+s) is (12+14) = 26

Step-by-step explanation:

Well, first let us solve equation of 11 (s-1) = 13 (r-1), which results in 11s-11=13r-13. Hence, 11s+2=13r. It is stated that r and s both are integers and greater than 1.

To make sure that r and s are integers, the least value of s must be equal to 14 (s=14) then the least value of r becomes 12 (r=12).

Finally, the least value of (r+s) is (12+14) = 26.