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5 January, 15:36

2i^4-5i^3+3i^2+√-81 rewritten in a+bi form?

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  1. 5 January, 16:01
    0
    -1 + 14i.

    Step-by-step explanation:

    i^2 = - 1.

    i^4 = i^2 * i^2

    = - 1 * - 1 = 1.

    i^3 = i^2 * i = - i.

    √-81 = i√81 = 9i.

    So

    2i^4-5i^3+3i^2+√-81

    = 2 - (5 * - i) - 3 + 9i

    = - 1 + 5i + 9i

    = - 1 + 14i.
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