For the numerator to have (x-8) as a factor, it's constant term must be what

Question

Emmett Haynes

Mathematics

18 June, 18:25

For the numerator to have (x-8) as a factor, it's constant term must be what

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Answers (1)

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Annika Dyer · Answer 1

Step-by-step explanation:

Right now the numerator is x^2 - 10x + 14, we need to add 2 to the constant of the numerator expression to get x^2 - 10x + 16.

For the numerator to have (x-8) as a factor, its constant term must be 16.