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7 March, 06:21

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the extreme values of the function subject to the given constraint. f (x, y, z) = 10x + 10y + 4z; 5x2 + 5y2 + 4z2 = 44

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  1. 7 March, 06:32
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    The expression

    10 x + 10 y + 4 z + λ (5 x^2 + 5 y^2 + 4 z^2 - 44)

    has partial derivatives with respect to x, y, z, and λ of

    10 + 10 x λ

    10 + 10 y λ

    4 + 8 z λ

    -44 + 5 x^2 + 5 y^2 + 4 z^2

    Setting these to zero and solving simultaneously gives the solutions

    (x, y, z, λ) = (2, 2, 1, - 1/2)

    (x, y, z, λ) = (-2, - 2, - 1, 1/2)

    The corresponding extreme values of f (x, y, z) are 44 and - 44.
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