How do you solve

f (x) = -2 (x+3) ^2 = 5

x = (-6+/-sqrt (10) * i) / 2

Step-by-step explanation:

-2 (x+3) ^2=5

-2 (x+3) (x+3) = 5

-2 (x^2+3x+3x+9) = 5

-2 (x^2+6x+9) = 5

-2x^2-12x-18=5

-2x^2-12x-18-5=0

-2x^2-12x-23=0

2x^2+12x+23=0

Apply the quadratic formula,

you get x = (-6+/-sqrt (10) * i) / 2.