Which of the following represents this function written in standard form? y=3 (x-1) (x+6)

y = 3x^2+15x-18

Step-by-step explanation:

Parabola has an equation with one variable in degree 2 and other in degree 1.

Given that y=3 (x-1) (x+6) is the function.

y is of degree 1 and x of degree 2

Standard form of these types of parabolas would be

y = ax^2+bx+c.

To make the given equation in standard form, we multiply all factors on the right side

y = 3 (x-1) (x+6) = 3 (x^2+5x-6)

= 3x^2+15x-18

a=3 b = 15 and c = -18

y = 3x^2+15x-18 is the standard form of the parabola

y = 3x^2 + 15x - 18

Step-by-step explanation:

To represent the function y = 3 (x - 1) (x + 6), start by by expanding the equation by multiplying the common factor with each term inside the brackets to get:

y = 3 (x - 1) (x + 6)

y = (3x - 3) (x + 6)

Now multiply both the terms with each other to get:

y = 3x^2 + 18x - 3x - 18

Arrange the like terms together and add them:

y = 3x^2 + 15x - 18

Hence, y = 3x^2 + 15x - 18 is the standard form of the given function.