Radio signals travel at a rate of 3x10^8 meter per second. How many seconds would it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 9.610^6 meters? (Hint: Time divide by speed.)

A) 3.210^2 seconds

B) 3.210^-2 seconds

C) 3.13 10^1seconds

D) 2.88*10^15 seconds

Question

15 April, 05:54

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Ahmad Ellis · Answer 1

Distance = velocity x time

distance = 9.6 x 10^15 meters

velocity = 3x10^8 meters/second

time = distance / velocity = m / (m/s) = s