Find four consecutive integers whose sum is 86

Four consecutive integers: x, (x+1), (x+2), and (x+3)

sum them up and get 86

x + x+1 + x+2 + x+3 = 86

now solve for x, the smallest one

4x + 6 = 86

4x = 80

x = 20

so the numbers are 20, 21, 22, and 23