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6 November, 15:15

The population that you're interested in has a mean of 60 and a standard deviation of 72 Step 2 of 2: If you calculate a (n) 93.12 % Confidence Interval on the Mean, what will your Margin of Error be? (Round to 2 decimal places.)

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  1. 6 November, 16:12
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    Z = 8.41

    Step-by-step explanation:

    Given that standard deviation = 72

    Mean = 60

    Z = marginal error

    Z = 72/√60

    Z = 72/7.746

    Z = (9.036) (0.9312)

    Z = 8.41
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